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Question

Common salt obtained from sea-water contains 96% NaCl by mass. The approximate number of molecules of NaCl present in 10.0 g of the common salt is:
(At.wt.Na=23 g)

A
1021
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B
1022
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C
1023
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D
1024
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Solution

The correct option is C 1023
Mass of NaCl=10×0.96=9.6 gm
moles of NaCl=9.658.5 mol

Number of molecules=number of moles ×NA=9.658.5×6.023×10231023

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