Question

Compare and arrange in ascending order:
9.998, 9.989, 9.899, 9.999

• A. 9.998, 9.989, 9.999, 9.899
• B. 9.998, 9.989, 9.999, 9.899
• C. 9.899, 9.989, 9.998, 9.999
• D. 9.999, 9.899, 9.998, 9.989

Answer 1

The correct option is C

9.899, 9.989, 9.998, 9.999

Comparing digits in the tenths places of 9.998, 9.989, 9.899, 9.999:
8 (9.899) < 9 (9.999 , 9.998 , 9.989)
Hence 9.899 is the smallest decimal of the lot.

Comparing the digits in the hundredths places of 9.999, 9.998 and 9.989, we have
8 (9.989) < 9 (9.999 and 9.998 ).
Hence, 9.989 < 9.999 and 9.998.

Comparing the digits in the thousandths places of 9.999 and 9.998, we have
9 (9.999) > 8 (9.998).
Hence, the given decimals arranged in ascending order is as follows:
9.899, 9.989, 9.998, 9.999