Compare the area of regions I and II.

None of these.

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I < II

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I = II

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I > II

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Solution

The correct option is C
I = II

Area of region I is equal to the area of region II.

Area of region I is equal to the area of the upper quarter of the circle subtracted from the area of the square.

Similarly area of region II is equal to the area ofthe lower quarter of the circle subtracted from the area of the square.

Hence the area of region I = area of region II.

Suggest Corrections

Similar questions

Which of the following are isobars?

i) $_{18}^{40} A r$
ii) $_{6}^{14} C$
iii) $_{20}^{40} C a$
iv) $_{7}^{14} N$

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