Question

Compare the areas of a square of side $15cm$ and a rectangle of length $11cm$ and breadth $8cm$. Which figure has the greater area and by how much?

Answer 1

Given side of square = 15 cm

then area of square$=(side{)}^2$

area of square $=(15{)}^2=225c{m}^2$

area length of rectangle = 11 cm

breadth of rectangle = 8 cm

Then area of rectangle $=l\times b=11\times 8-88c{m}^2$

$\therefore$ area of square > area of rectangle

&

diff in area $=225-88=137c{m}^2$