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Polar Covalent Compounds

Compare the b...

Question

Compare the bond length a and b.
$C H_{3} - O | | C - O - C H_{3};$
a b

a = b

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b > a

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b < a

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Impossible to predict

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Solution

The correct option is B $b > a$
Here $a$ has a double bond character slightly whereas $b$ is just a single bond.
$∴$ Order of bond length is $b > a$

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H - C \equiv C a - C \equiv C b - C H_{3}

a

b

a

b

C H_{3} - O | | C - a O - b C H_{3}

C H_{3} - O | | C - C H_{3} (A), C H_{3} - O | | C - H (B), C H_{3} - O | | C - C H_{2} - C l (C), H - O | | C - H (D), C l - C H_{2} - O | | C - H (E)

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^{18} O H + C H_{3} C H_{2} O H^{+} A

B

C H_{3} - O (A) - + C H_{2}, C H_{3} - N H (B) - + C H_{2}, C H_{3} - S (C) - + C H_{2}

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