Compare the $C H$ bond strength in $C_{2} H_{6}, C_{2} H_{4}$ and $C_{2} H_{2}$ .

Open in App

Solution

Bond length order follows- triple bond < double bond < single bond.

Bond strength is inversely proportional to bond length.
So, the order of bond strength will be :
triple bond > double bond > single bond

So, the correct orders of given compounds will be :
$C_{2} H_{2} > C_{2} H_{4} > C_{2} H_{6}$

Suggest Corrections

Similar questions

C - H

I \to C_{2} H_{2},

I I \to C_{2} H_{4},

I I I \to C_{2} H_{6}

C_{2} H_{6}, C_{2} H_{4}

C_{2} H_{2}

C

C H_{4}, C_{2} H_{6}, C_{3} H_{8}, C_{2} H_{4}, C_{2} H_{2}, H_{2} C_{2} O_{4}

C O_{2}

C_{2} H_{4}

C_{2} H_{2}

C_{6} H_{6}

C_{2} H_{6}

C_{2} H_{2}

C_{2} H_{4}

C_{2} H_{6}

Join BYJU'S Learning Program