Question

Compare the following pairs of surds.

$\sqrt{11},\sqrt{13}$

• A. $\sqrt{11}\ne \sqrt{13}$
• B. $\sqrt{11}>\sqrt{13}$
• C. $\sqrt{11}<\sqrt{13}$
• D. $\sqrt{11}=\sqrt{13}$

Answer 1

The correct option is C $\sqrt{11}<\sqrt{13}$

We know that $4<9$. Now their square roots are , $\sqrt{4}=2and\sqrt{9}=3$.
Since, $2<3$. $\sqrt{4}<\sqrt{9}$
Similarly, as $11<13,\sqrt{11}<\sqrt{13}$