Compare the given ratios
$1 : 2, 12 : 24$ .

1 : 2 < 12 : 24

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1 : 2 > 12 : 24

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1 : 2 = 12 : 24

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None of the above.

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Solution

The correct option is C $1 : 2 = 12 : 24$
Given ratio is $1 : 2$ and $12 : 24 = 1 : 2$
Hence, both the ratios are equal.

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t^{24}

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t^{24}

(1 + t^{2})^{12} (1 + t^{12}) (1 + t^{24})

\frac{1}{{log}_{6} 24} + \frac{1}{{log}_{12} 24} + \frac{1}{{log}_{8} 24} = 2

\frac{1}{{log}_{6} 24} + \frac{1}{{log}_{12} 24} + \frac{1}{{log}_{8} 24} = 2

t^{24}

{(1 + t^{2})}^{12} (1 + t^{12}) (1 + t^{24})

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