Question

Compare the results of the given equations.

$12\frac{1}{21}+4\frac{3}{21}=A$ $10\frac{5}{21}+5\frac{6}{21}=B$

• A. $A=B$
• B. None of the above
• C. $B>A$
• D. $A>B$

Answer 1

The correct option is D $A>B$

Let’s solve the problem stepwise.

● When we add or subtract mixed fractions, we add or subtract their whole parts together and their fractional parts together.

● To find A, let’s add $12\frac{1}{21}$ and $4\frac{3}{21}$

● $12\frac{1}{21}+4\frac{3}{21}=12+\frac{1}{21}+4+\frac{3}{21}$

$=12+4+\frac{1}{21}+\frac{3}{21}$

$=16+\frac{1+3}{21}$

$=16+\frac{4}{21}=16\frac{4}{21}$

● So, $A=16\frac{4}{21}$

● Now, to find B, let’s add $10\frac{5}{21}$ and $5\frac{6}{21}$

● $10\frac{5}{21}+5\frac{6}{21}=10+\frac{5}{21}+5+\frac{6}{21}$

$=15+\frac{5+6}{21}$

$=15+\frac{11}{21}=15\frac{11}{21}$

● So, $B=15\frac{11}{21}$

● Clearly, $A>B$.

Thus, A is the correct option.