Compare the stabilities of the following two compounds (A) and (B):
A: $c i s - 1 - e t h y l - 3 - m e t h y l$ $c y c l o h e x a n e$ B: $t r a n s - 1 - e t h y l - 3 - m e t h y l$ $c y c l o h e x a n e$

A is more stable

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B is more stable

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A and B are of equal stability

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No comparison can be made

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Solution

The correct option is A A is more stable
A will be more stable because in A $C H_{3}$ and $C H_{3} C H_{2}$ groups are in equatorial position, so there will be no hindered interaction. But in B, due to axial $- C H_{3}$ groups there will be steric interaction with axial $H -$ atoms.

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