Compare the two ratios 7-12 and 9-16

The correct option is C 7/12 gt; 9/16To compare 7/12 and9/16 we have to find 7 X 16 and 9 X 12. As 7 X 16(112) gt; 9 X 12(108), we can say 7/12 gt; 9/ ...

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Byju's Answer

Standard VIII

Mathematics

Increasing or Decreasing a Ratio

Compare the t...

Question

Compare the two ratios $\frac{7}{12}$ and $\frac{9}{16}$ .

\frac{7}{12} = \frac{9}{16}

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\frac{7}{12} < \frac{9}{16}

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\frac{7}{12} > \frac{9}{16}

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\frac{7}{12} \geq \frac{9}{16}

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Solution

The correct option is C $\frac{7}{12} > \frac{9}{16}$
To compare $\frac{7}{12}$ and $\frac{9}{16}$ we have to find 7 X 16 and 9 X 12.
As 7 X 16(112) > 9 X 12(108), we can say $\frac{7}{12}$ > $\frac{9}{16}$ .
Therefore $\frac{7}{12}$ > $\frac{9}{16}$

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Similar questions

Q. Compare the ratios

4 : 5

and

7 : 9.

Q. Compare which ratio is greater?

7 : 16

13 : 24

Q. The pie diagrams on the monthly expenditure of two families

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Q. Add the following fractions.
(a)

\frac{7}{12}

and

\frac{3}{8}

(b)

\frac{9}{16}

and

\frac{7}{12}

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

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Compare the two ratios 712 and 916.

The correct option is C 712>916To compare 712 and916 we have to find 7 X 16 and 9 X 12. As 7 X 16(112) > 9 X 12(108), we can say 712 > 916. Therefore 712 > 916

Compare the two ratios $\frac{7}{12}$ and $\frac{9}{16}$ .

The correct option is C $\frac{7}{12} > \frac{9}{16}$
To compare $\frac{7}{12}$ and $\frac{9}{16}$ we have to find 7 X 16 and 9 X 12.
As 7 X 16(112) > 9 X 12(108), we can say $\frac{7}{12}$ > $\frac{9}{16}$ .
Therefore $\frac{7}{12}$ > $\frac{9}{16}$