Question

Compare the value of K with A:

$K=\frac{4}{3}\times \frac{3}{2}\times \frac{3}{8}\times A$

• A. Cannot be determined
• B. $K>A$
• C. $K=A$
• D. $K<A$

Answer 1

The correct option is D $K<A$

$K=\frac{4}{3}\times \frac{3}{2}\times \frac{3}{8}\times A$

$=(\frac{4}{3}\times \frac{3}{2})\times \frac{3}{8}\times A$


$=\left(\frac{4\times 3}{3\times 2}\right)\times \frac{3}{8}\times A$

$=\left(\frac{12}{6}\right)\times \frac{3}{8}\times A$

$=2\times \frac{3}{8}\times A$

$=\frac{2\times 3}{1\times 8}\times A$

$=\frac{6}{8}\times A$

$=\frac{6÷2}{8÷2}\times A$

$K=\frac{3}{4}\times A$


$\therefore K<A$