Question

Comparing the average donations from the two cities, New York and California using the appropriate comparison sign, you get
New York California

• A. <
• B. >
• C. =

Answer 1

The correct option is A <

You know,
$Mean=$ $\frac{Sumoftheobservations}{Numberoftheobservations}$

For New York, the numbers are $3,2,0,5,$ and $6$

∴ Mean of the values
$=\frac{3+2+0+5+6}{5}$ $=$ $\frac{16}{5}$
Converting the fraction into decimal,
you get: $\frac{16}{5}$ $=$ $\frac{16\times 2}{5\times 2}$ $=$ $\frac{32}{10}$ $=3.2$

Rounding off to the nearest whole number,
$3.2$ becomes $3$.

∴ The mean of average donations from New York can be rounded off to the nearest whole number i.e., $3$.

For California, the numbers are $8,9,6,1,$ and $4$

∴ Mean of the values
$=\frac{8+9+6+1+4}{5}$ $=$ $\frac{28}{5}$

Converting the fraction into decimal,
we get: $\frac{28}{5}$ $=$ $\frac{28\times 2}{5\times 2}$ $=$ $\frac{56}{10}$ $=5.6$

Rounding off to the nearest whole number,
$5.6$ becomes $6$.

∴ The mean of average donations from California can be rounded off to the nearest whole number i.e., $6$.

You know, $3<6$

Hence, average donations
from $NewYork$ $<$ from $California$