Question

Comparing the average donations from two cities, Delhi and Mumbai, using the appropriate comparison sign, we get
Delhi Mumbai

• A. >
• B. <
• C. =

Answer 1

The correct option is B <

$Mean=$ $\frac{Sumoftheobservations}{Numberoftheobservations}$


For Delhi, the numbers are
3, 2, 0, 5 and 6

∴ Mean of the values

$=\frac{3+2+0+5+6}{5}$ $=$ $\frac{16}{5}$

Converting the fraction into decimal,
we get:

$\frac{16}{5}$ $=$ $\frac{16\times 2}{5\times 2}$ $=$ $\frac{32}{10}$ $=3.2$

Rounding off to the nearest whole number, 3.2 becomes 3.

∴ The mean of the yearly donations from Delhi can be rounded off to the nearest whole number as 3.


For Mumbai, the numbers are
8, 9, 6, 1 and 4

∴ Mean of the values

$=\frac{8+9+6+1+4}{5}=\frac{28}{5}$

Converting the fraction into decimal,
we get:

$\frac{28}{5}=\frac{28\times 2}{5\times 2}=\frac{56}{10}=5.6$

Rounding off to the nearest whole number, 5.6 becomes 6.

∴ The mean of yearly donations from Mumbai can be rounded off to the nearest whole number as 6.

As we know, 3 < 6

Hence, comparing the mean yearly donations from Delhi and Mumbai, we find:
Delhi < Mumbai