Question

Complete and balance the equation

${\mathrm{CaCO}}_3+\mathrm{HCl}\to$

Answer 1

Step 1: When Calcium carbonate $\left({\mathrm{CaCO}}_3\right)$ reacts with Hydrochloric acid $\left(\mathrm{HCl}\right)$ then it gives Calcium chloride$\left({\mathrm{CaCl}}_2\right)$, water$\left({\mathrm{H}}_2\mathrm{O}\right)$, and carbon dioxide $\left({\mathrm{CO}}_2\right)$as a gas.

${\mathrm{CaCO}}_3+\mathrm{HCl}\to {\mathrm{CaCl}}_2+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

Step 2: Balancing the given chemical equation step by step as:

1. Count the number of atoms in both the reactant and product sides.

Reactant	Product
Ca- 1	Ca - 1
C - 1	C - 1
O - 3	O - 3
H - 1	H - 2
Cl - 1	Cl - 2

Here, Oxygen, Carbon, and Calcium are balanced but Hydrogen and Chlorine are not balanced on both sides.

2: Multiply $\mathrm{HCl}$ by 2 on the reactant side to balance Chlorine on both sides.

${\mathrm{CaCO}}_3+2\mathrm{HCl}\to {\mathrm{CaCl}}_2+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

3: Count the number of atoms in both the reactant and product sides.

Reactant	Product
Ca- 1	Ca - 1
C - 1	C - 1
O - 3	O - 3
H - 2	H - 2
Cl - 2	Cl - 2

Here, Calcium, Oxygen, Carbon, Hydrogen, and Chlorine are balanced on both sides. Thus, the equation is balanced now.

Step 3: Therefore, the balanced chemical equation is as:

${\mathrm{CaCO}}_3+2\mathrm{HCl}\to {\mathrm{CaCl}}_2+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$