Question

Complete and balance the equation

$\mathrm{CuO}+{\mathrm{H}}_2{\mathrm{SO}}_4\to$

Answer 1

Step 1: When Copper oxide $\left(\mathrm{CuO}\right)$ reacts with Sulphuric acid $\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$, then it gives Copper sulphate $\left({\mathrm{CuSO}}_4\right)$, and water$\left({\mathrm{H}}_2\mathrm{O}\right)$.

$\mathrm{CuO}+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{CuSO}}_4+{\mathrm{H}}_2\mathrm{O}$

Step 2: Balancing step by step as;

1. Count the number of atoms in both the reactant and product sides.

Reactant	Product
Cu - 1	Cu - 1
O - 5	O - 5
H - 2	H - 2
S - 1	S - 1

Here the atoms of Copper, Sulphur, Oxygen, and Hydrogen are balanced on both sides. Thus, the given chemical equation is balanced.

Step 3: Balanced chemical equation:

$\mathrm{CuO}+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{CuSO}}_4+{\mathrm{H}}_2\mathrm{O}$