Question

Complete and balance the equation

$\mathrm{KOH}+{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\to$

Answer 1

Step 1: When Potassium hydroxide $\left(\mathrm{KOH}\right)$ reacts with Ammonium sulphate $\left[{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\right]$, then it gives Potassium sulphate$\left({\mathrm{K}}_2{\mathrm{SO}}_4\right)$, water $\left({\mathrm{H}}_2\mathrm{O}\right)$, and ammonia$\left({\mathrm{NH}}_3\right)$ as a gas.

$\mathrm{KOH}+{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\to {\mathrm{K}}_2{\mathrm{SO}}_4+{\mathrm{H}}_2\mathrm{O}+{\mathrm{NH}}_3$

Step 2: Balancing step by step as:

1. Count the number of atoms in both the reactant and product sides.

Reactant	Product
K - 1	K - 2
O - 5	O - 5
H - 9	H - 5
N - 2	N - 1
S - 1	S - 1

Here, atoms of Sulphur and Oxygen are balanced but Potassium, Hydrogen and Nitrogen atoms are not balanced on both sides.

2. Multiply $\left(\mathrm{KOH}\right)$ by 2 on the reactant side to balance atoms of Potassium on both sides.

$2\mathrm{KOH}+{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\to {\mathrm{K}}_2{\mathrm{SO}}_4+{\mathrm{H}}_2\mathrm{O}+{\mathrm{NH}}_3$

3. Count the number of atoms in both the reactant and product sides.

Reactant	Product
K - 2	K - 2
O - 6	O - 5
H - 10	H - 5
N - 2	N - 1
S - 1	S - 1

Here, Sulphur and Potassium are balanced but Oxygen, Hydrogen and Nitrogen are not balanced on both sides.

4. Multiply $\left({\mathrm{NH}}_3\right)$ by 2 on the product side to balance Nitrogen on both sides.

$2\mathrm{KOH}+{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\to {\mathrm{K}}_2{\mathrm{SO}}_4+{\mathrm{H}}_2\mathrm{O}+2{\mathrm{NH}}_3$

5. Count the number of atoms in both the reactant and product sides.

Reactant	Product
K - 2	K - 2
O - 6	O - 5
H - 10	H - 8
N - 2	N - 2
S - 1	S - 1

Here atoms of Sulphur, Nitrogen and Potassium are balanced but Oxygen and Hydrogen atoms are not balanced on both sides.

6. Multiply$\left({\mathrm{H}}_2\mathrm{O}\right)$ by 2 on the product side to balance Nitrogen atoms on both sides.

$2\mathrm{KOH}+{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\to {\mathrm{K}}_2{\mathrm{SO}}_4+2{\mathrm{H}}_2\mathrm{O}+2{\mathrm{NH}}_3$

7. Count the number of atoms in both the reactant and product sides.

Reactant	Product
K - 2	K - 2
O - 6	O - 6
H - 10	H - 10
N - 2	N - 2
S - 1	S - 1

Now, the equation is balanced as all atoms are equal on both sides.

Step 3 :

Therefore, the balanced chemical equation is:

$2\mathrm{KOH}+{\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4\to {\mathrm{K}}_2{\mathrm{SO}}_4+2{\mathrm{H}}_2\mathrm{O}+2{\mathrm{NH}}_3$