Question

Complete and balance the equation.

${\mathrm{N}}_2+{\mathrm{H}}_2\to$

Answer 1

When nitrogen and hydrogen react together it gives Ammonia

• The complete reaction is:

${\mathrm{N}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right)\to {\mathrm{NH}}_3\left(\mathrm{g}\right)$

• Here the reaction is not balanced. as the number of reactants and products are not equal. let's balance nitrogen since it is 2 on the reactant side and 1 on the product side.

${\mathrm{N}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right)\to 2{\mathrm{NH}}_3\left(\mathrm{g}\right)$

• Now the number of atoms of nitrogen is equal on both sides. let us make the number of atoms of hydrogen equal on both sides since it is 6 on the product side and 2 on the reactant side

${\mathrm{N}}_2\left(\mathrm{g}\right)+3{\mathrm{H}}_2\left(\mathrm{g}\right)\to 2{\mathrm{NH}}_3\left(\mathrm{g}\right)$

• Hydrogen combines with nitrogen in the ratio of 3:1 by volume, in the presence of iron as catalyst and molybdenum as a promoter at a pressure of 200 atm and 450⁰C giving ammonia

$\underset{\mathbf{Nitrogen}\mathbf{}\mathbf{gas}}{{\mathbf{N}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}}\mathbf{+}\mathbf{}\underset{\mathbf{Hydrogen}\mathbf{}\mathbf{gas}}{\mathbf{3}{\mathbf{H}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{}}\underset{\mathbf{Fe}\mathbf{/}\mathbf{Mo}}{\overset{\mathbf{200}\mathbf{}\mathbf{atm}\mathbf{}{\mathbf{450}}^{°}\mathbf{C}}{\mathbf{\rightleftharpoons }}}\mathbf{}\underset{\mathbf{Ammonia}}{\mathbf{2}{\mathbf{NH}}_{\mathbf{3}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}}$

This is the balanced chemical equation.