Question

Complete and balance the equation

${\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to$

Answer 1

Step 1: When Sodium bicarbonate $\left({\mathrm{NaHCO}}_3\right)$ reacts with Sulphuric acid $\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$ then it gives Sodium sulphate$\left({\mathrm{Na}}_2{\mathrm{SO}}_4\right)$, water $\left({\mathrm{H}}_2\mathrm{O}\right)$, and Carbon dioxide$\left({\mathrm{CO}}_2\right)$ as a gas.

${\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{Na}}_2{\mathrm{SO}}_4+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

Step 2: Balancing the given chemical equation step by step as:

1. Count the number of atoms in both the reactant and product sides.

Reactant	Product
Na- 1	Na - 2
C - 1	C - 1
O - 7	O - 7
H - 3	H - 2
S - 1	S- 1

Here, Oxygen, Carbon and Sulphur are balanced but Hydrogen and Sodium are not balanced on both sides.

2: Multiply ${\mathrm{NaHCO}}_3$ by 2 on the reactant side to balance Sodium and Hydrogen on both sides.

$2{\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{Na}}_2{\mathrm{SO}}_4+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

3: Count the number of atoms in both the reactant and product sides.

Reactant	Product
Na- 2	Na - 2
C - 2	C - 1
O - 10	O - 7
H - 4	H - 2
S - 1	S- 1

Here, Sodium and Sulphur are balanced on both sides but Carbon, Hydrogen and Oxygen are not balanced on both sides.

4: Multiply ${\mathrm{CO}}_2$ by 2 on the product side to balance Carbon and Oxygen on both sides.

$2{\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{Na}}_2{\mathrm{SO}}_4+{\mathrm{H}}_2\mathrm{O}+2{\mathrm{CO}}_2$

5: Count the number of atoms in both the reactant and product sides.

Reactant	Product
Na- 2	Na - 2
C - 2	C - 2
O - 10	O - 9
H - 4	H - 2
S - 1	S- 1

Here, Sodium, Carbon and Sulphur are balanced on both sides but Hydrogen and Oxygen are not balanced on both sides.

6: Multiply ${\mathrm{H}}_2\mathrm{O}$ by 2 on the product side to balance Hydrogen and Oxygen on both sides.

$2{\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{Na}}_2{\mathrm{SO}}_4+2{\mathrm{H}}_2\mathrm{O}+2{\mathrm{CO}}_2$

7: Count the number of atoms in both the reactant and product sides.

Reactant	Product
Na- 2	Na - 2
C - 2	C - 2
O - 10	O - 10
H - 4	H - 4
S - 1	S- 1

Now, the equation is balanced as all the atoms are equal on both sides.

Step 3: Balanced chemical equation is:

$2{\mathrm{NaHCO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{Na}}_2{\mathrm{SO}}_4+2{\mathrm{H}}_2\mathrm{O}+2{\mathrm{CO}}_2$