Question

Complete and balance the equation

$\mathrm{NaOH}+{\mathrm{NH}}_4\mathrm{Cl}\to$

Answer 1

Step 1: When Sodium hydroxide $\left(\mathrm{NaOH}\right)$ reacts with Ammonium chloride $\left({\mathrm{NH}}_4\mathrm{Cl}\right)$, then it gives Sodium chloride$\left(\mathrm{NaCl}\right)$, water$\left({\mathrm{H}}_2\mathrm{O}\right)$, and ammonia$\left({\mathrm{NH}}_3\right)$ as a gas.

$\mathrm{NaOH}+{\mathrm{NH}}_4\mathrm{Cl}\to \mathrm{NaCl}+{\mathrm{H}}_2\mathrm{O}+{\mathrm{NH}}_3$

Step 2: Balancing step by step as:

1. Count the number of atoms in both the reactant and product sides.

Reactant	Product
Na - 1	Na - 1
O - 1	O - 1
H - 5	H - 5
N - 1	N - 1
Cl - 1	Cl - 1

Here atoms of Sodium, Nitrogen, Chlorine, Oxygen, and Hydrogen are balanced on both sides. Thus, the chemical equation is balanced.

Step 3: The balanced chemical equation is:

$\mathrm{NaOH}+{\mathrm{NH}}_4\mathrm{Cl}\to \mathrm{NaCl}+{\mathrm{H}}_2\mathrm{O}+{\mathrm{NH}}_3$