Question

Complete and balance the following equation.

$\mathrm{Al}+\mathrm{KOH}\to$

Answer 1

Chemical equation -

$\underset{\mathrm{Aluminium}}{\mathrm{Al}\left(\mathrm{s}\right)}+\underset{\mathrm{Potassium}\mathrm{hydroxide}}{\mathrm{KOH}\left(\mathrm{s}\right)}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}\to \underset{\mathrm{Potassium}\mathrm{aluminate}}{{\mathrm{KAlO}}_2\left(\mathrm{aq}\right)}+\underset{\mathrm{Hydrogen}}{{\mathrm{H}}_2\left(\mathrm{g}\right)(\uparrow )}$

Reactant side	Product side
Aluminium (Al)= 1 x 2 = 2	Aluminium(Al) = 1 x 2 = 2
Potassium (K) = 1 x 2 = 2	Potassium (K) = 1 x 2 = 2
Oxygen (O) = 1 x 2 + 1 x 2 = 4	Oxygen (O) = 2 x 2 = 4
Hydrogen(H) = 1 x 2 + 2 x 2 = 6	Hydrogen (H) = 2 x 3 = 6

Balanced equation - When aluminium (Al) reacts with potassium hydroxide (KOH) in an aqueous solution it forms potassium aluminate (KAlO₂) and evolved hydrogen (H₂) gas.

$\underset{\mathrm{Aluminium}}{2\mathrm{Al}\left(\mathrm{s}\right)}+\underset{\mathrm{Potassium}\mathrm{hydroxide}}{2\mathrm{KOH}\left(\mathrm{s}\right)}+\underset{\mathrm{Water}}{2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}\to \underset{\mathrm{Potassium}\mathrm{aluminate}}{2{\mathrm{KAlO}}_2\left(\mathrm{aq}\right)}+\underset{\mathrm{Hydrogen}}{3{\mathrm{H}}_2\left(\mathrm{g}\right)(\uparrow )}$