Complete and balance the following equations :

(a) $N a O H + . . . . . . . . . . . . . ⟶$ $N a_{2} S O_{4} + H_{2} O$

(b) $C a (O H)_{2}$ + ............. $⟶$ $C a C O_{3} + H_{2} O$

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Solution

(a)

$N a O H + H_{2} S O_{4} ⟶$ $N a_{2} S O_{4} + H_{2} O$

In this equation, Sodium (Na) and Hydrogen (H) atoms are not balanced. There are 2 atoms of Sodium (Na) on Right Hand Side, so we can multiply NaOH with 2 on Left Hand Side. This balances the Sodium (Na) atoms. Now, Hydrogen (H) and Oxygen (O)atoms are unbalanced. Again, we multiply 2 with Water on Left Hand Side. Thus all the elements are balanced.

$2 N a O H + H_{2} S O_{4} ⟶$ $N a_{2} S O_{4} + 2 H_{2} O$

(b)

$C a (O H)_{2} + C O_{2} ⟶ C a C O 3 + H_{2} O$

Here the basic skeletal equation itself is balanced. So we dont have to do anything more.

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