Question

Complete and balance the following equations:

$\mathrm{KCl}+{\mathrm{H}}_2{\mathrm{SO}}_4(\mathrm{conc}.)\to$

Answer 1

1. When Potassium chloride undergoes a reaction with Sulphuric acid, Hydrogen chloride and Potassium bisulphate is form.
2. The chemical reaction is,
   $$\begin{gathered} \mathrm{KCl}\left(\mathrm{s}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)\to \mathrm{HCl}\left(\mathrm{g}\right)+{\mathrm{KHSO}}_4\left(\mathrm{s}\right) \\ \mathrm{Potassium}\mathrm{Sulphuric}\mathrm{Hydrogen}\mathrm{Potassium} \\ \mathrm{chloride}\mathrm{acid}\mathrm{chloride}\mathrm{bisulphate} \end{gathered}$$
3. The above chemical equation is balanced because the number of atoms is equal on the product and reactant sides.
4. So, the complete and balanced equation is,

$$\begin{gathered} \mathrm{KCl}\left(\mathrm{s}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{l}\right)\to \mathrm{HCl}\left(\mathrm{g}\right)+{\mathrm{KHSO}}_4\left(\mathrm{s}\right) \\ \mathrm{Potassium}\mathrm{Sulphuric}\mathrm{Hydrogen}\mathrm{Potassium} \\ \mathrm{chloride}\mathrm{acid}\mathrm{chloride}\mathrm{bisulphat}e \end{gathered}$$