Question

Complete and balance the following reaction.

${\mathrm{Cl}}_2+2\mathrm{NaBr}\to \mathrm{\_\_\_\_}+{\mathrm{Br}}_2\uparrow$

Answer 1

$\underset{\mathrm{Chlorine}}{{\mathrm{Cl}}_2}+\underset{\mathrm{Sodium}\mathrm{bromide}}{2\mathrm{NaBr}}\to \underset{\mathrm{Sodium}\mathrm{chloride}}{2\mathrm{NaCl}}+\underset{\mathrm{Bromine}}{{\mathrm{Br}}_2\uparrow }$

Chlorine after reacting with Sodium bromide, displaces bromine to form Sodium chloride and bromine gas is liberated.

Balancing-

• We multiply the reactants and products with a number using hit and trial method in order to make the number of atoms in reactants and products are same.
• Balancing chemical equation follows the law of conservation of mass.