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Question

# Complete and balance the following reaction :${\mathrm{KClO}}_{3}\stackrel{∆}{\to }$

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Solution

## When Potassium chlorate is heated we get Potassium chloride and Oxygen.Hence, we get the equation- ${\mathrm{KClO}}_{3}\stackrel{∆}{\to }\mathrm{KCl}+{\mathrm{O}}_{2}$Balancing the equation-AtomsReactantProductK11Cl11O32We multiply the Oxygen molecule on the product side by 3 and we get 6 atoms of Oxygen on the product side.To get 6 Oxygen atoms on the reactant side we multiply the Potassium chlorate molecule by 2.We get extra Potassium and Chlorine molecule multiplied by 2 to finally balance the equation.AtomsReactantProductK22Cl22O66Hence, the complete balanced equation for the above reaction is-$\underset{\mathrm{Potassium}\mathrm{chlorate}}{2{\mathrm{KClO}}_{3}\left(\mathrm{s}\right)}\stackrel{∆}{\to }\underset{\mathrm{Potassium}\mathrm{chloride}}{2\mathrm{KCl}\left(\mathrm{s}\right)}+\underset{\mathrm{Oxygen}}{3{\mathrm{O}}_{2}\left(\mathrm{g}\right)}$

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