Question

Complete and balance the following reaction :

${\mathrm{PbO}}_2+{\mathrm{SO}}_2\to$

Answer 1

Lead oxide is reacting with Sulphur dioxide to form lead sulphate.

$\underset{\mathrm{Lead}\mathrm{oxide}}{{\mathrm{PbO}}_2\left(\mathrm{s}\right)}+\underset{\mathrm{Sulphur}\mathrm{dioxide}}{{\mathrm{SO}}_2\left(\mathrm{g}\right)}\to \underset{\mathrm{Lead}\mathrm{sulphate}}{{\mathrm{PbSO}}_4\left(\mathrm{s}\right)}$

When we count the atoms in the reactant part and product part we get an equal number of atoms on both sides.

Hence, the given equation is balanced as well.