Complete combustion of 3g of ethane gives x ×1022 molecules of water. The value of x is _____ [Round off to the Nearest Integer].
[Use: NA=6.023×1023; Atomic masses in u : C : 12.0; O : 16.0 : H : 1.0 ]
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Solution
Answer: 18 C2H63g+O2→2CO2+3H2O
Moles of C2H6=330=0.1 C2H60.1mol+O2→2CO2+3H2O0.3mol
No. of molecules of H2O=0.3×6.023×1023) =1.8069×1023 =18.069×1022