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Question

Complete combustion of 3 g of ethane gives x ×1022 molecules of water. The value of x is _____ [Round off to the Nearest Integer].
[Use: NA=6.023×1023; Atomic masses in u : C : 12.0; O : 16.0 : H : 1.0 ]

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Solution

Answer: 18
C2H63 g+O22CO2+3H2O
Moles of C2H6=330=0.1
C2H60.1 mol+O22CO2+3H2O0.3 mol

No. of molecules of H2O=0.3×6.023×1023)
=1.8069×1023
=18.069×1022

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