Domain and Range of Basic Inverse Trigonometric Functions
Complete solu...
Question
Complete solution set of tan2(sin−1x)>1 is :
A
(−1−1√2)∪(1√2,1)
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B
(−1√2,1√2)−{0}
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C
(−1,1)−{0}
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D
None of these
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Solution
The correct option is A(−1−1√2)∪(1√2,1) tan2(sin−1x)>1 ⇒tan(sin−1x)<−1 or tan(sin−1x)>1 ⇒−π2<sin−1x<−π4 or π4<sin−1x<π2 ⇒−1<x<−1√2 or 1√2<x<1 ⇒xϵ(−1−−1√2)∪(1√2,1)