Question

complete the addition -subtraction table :

Answer 1

$A=\frac{4}{7}+\frac{3}{7}=\frac{7}{7}=1$

$B=\frac{1}{7}+\frac{2}{7}=\frac{3}{7}$

$C=1-\frac{3}{7}=\frac{4}{7}$

$D=\frac{3}{7}-\frac{2}{7}=\frac{1}{7}$

$E=\frac{4}{7}-\frac{1}{7}=\frac{3}{7}$

Hence, $A=1,B=\frac{3}{7},C=\frac{4}{7},D=\frac{1}{7},E=\frac{3}{7}$.