Complete the following Me - H F Propyne EFind F

The correct option is B 3 bromoprop 1 yne The reaction of propyne with #160;N Bromosuccinimide(NBS) results in propargylic substitution and 3Bromoprop 1 ...

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Standard XII

Chemistry

Chemical Properties of Ethers

Complete the ...

Question

Complete the following
$\begin{matrix} M e \equiv H & N B S - --- \to + C C l_{4} & (F) P r o p y n e (E) \end{matrix}$
Find (F)

3 - b r o m o p r o p - 1 - e n e

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3 - b r o m o p r o p - 1 - y n e

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2 - b u t y n e

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3, 3, 3 - t r i b r o m o p r o p - 1 - y n e

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Solution

The correct option is B $3 - b r o m o p r o p - 1 - y n e$
The reaction of propyne with N-Bromosuccinimide(NBS) results in propargylic substitution and 3Bromoprop-1-yne forms. $H - C H_{2} - C \equiv C - H N - B r o m o s u c c i n i m i d e \to B r - C H_{2} - C \equiv C H$

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Similar questions

Q. What is the correct structure of

3

-Bromoprop-

1

-ene?

Q. The structure of 3-Bromoprop-1-ene is:

The IUPAC name of the compound having the formula $C H \equiv C - C H = C H_{2}$ is

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(c) 2-Methylpropane
(d) 3-Hexene
(e) Prop-1-yne

Q. The number of sigma and pi-bonds in but-1-ene-3-yne are:

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Complete the following Me≡HNBS−−−−→+CCl4(F)Propyne(E)Find (F)

The correct option is B 3−bromoprop−1−yneThe reaction of propyne with N-Bromosuccinimide(NBS) results in propargylic substitution and 3Bromoprop-1-yne forms. H−CH2−C≡C−HN−Bromosuccinimide→Br−CH2−C≡CH

Complete the following
$\begin{matrix} M e \equiv H & N B S - --- \to + C C l_{4} & (F) P r o p y n e (E) \end{matrix}$
Find (F)

The correct option is B $3 - b r o m o p r o p - 1 - y n e$
The reaction of propyne with N-Bromosuccinimide(NBS) results in propargylic substitution and 3Bromoprop-1-yne forms. $H - C H_{2} - C \equiv C - H N - B r o m o s u c c i n i m i d e \to B r - C H_{2} - C \equiv C H$