Question

Complete the following equation:
${\mathrm{FeSO}}_4.7H_{2}O\left(s\right)\stackrel{\Delta }{\to }\mathrm{FeO}(\mathrm{s)}+$+$7H_{2}O\left(g\right)$

• A. ${\mathrm{SO}}_3$
• B. ${\mathrm{SO}}_2$
• C. ${\mathrm{FeSO}}_4$

Answer 1

The correct option is A ${\mathrm{SO}}_3$

Sulphuric acid can be produced by thermal decomposition of copper (II) sulphate pentahydrate and ferrous (II) sulphate heptahydrate.
${\mathrm{CuSO}}_4.5H_{2}O\left(\mathrm{s)}\stackrel{\Delta }{\to }\mathrm{CuO}\right(\mathrm{s)}+5H_{2}O(\mathrm{g)}+{\mathrm{SO}}_3(\mathrm{g)}$
The ${\mathrm{SO}}_3$ and $H_{2}O$ combines to form dilute sulphuric acid.
Similarly,
${\mathrm{FeSO}}_4.7H_2\mathrm{O\; (s)}\stackrel{\Delta }{\to }\mathrm{FeO\; (s)}+{\mathrm{SO}}_3(g)+7H_{2}O(\mathrm{g)}$
Here, also dilute sulphuric acid is formed.