Complete the following ionic equations in reference to electrolysis and electroplating
$H + H \to______$

Open in App

Solution

Electrode reaction
The reduction half-reaction occurring at the cathode is given in this reaction.
The hydrogen atoms covalently bonded together to form a hydrogen molecule and it gets liberated at the cathode.
$H + H \to H_{2}$

Suggest Corrections

Similar questions

Complete the following ionic equations in reference to electrolysis and electroplating

${OH}^{-} -___\to_____$

Complete the following ionic equations in reference to electrolysis and electroplating

$1 . {Al}_{2} O_{3} ⇌_____+______2 . {Al}^{+ 3} +_____\to______3 . O^{- 2} -______\to_____$

Complete the following ionic equations in reference to electrolysis and electroplating

$1 . {PbBr}_{2} ⇌_____+______2 . {Pb}^{+ 2} +_____\to______3 . {Br}^{- 1} -______\to_____4 . Br + Br \to__________$

Complete the following ionic equations in reference to electrolysis and electroplating

$1 . Na [Ag {(CN)}_{2}] ⇌_____+______2 . H_{2} O ⇌______+_______3 . {Ag}^{+} +____\to_____4 . Ag -____\to______$

Join BYJU'S Learning Program