Complete the following reaction:
$2 NaOH (aq) + H_{2} {SO}_{4} (aq) \to$

{Na}_{2} {SO}_{4} (aq) + 2 H_{2} O (l)

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{Na}_{2} {SO}_{4} (aq) + 2 H_{2} S (g)

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{Na}_{2} O (aq) + 2 H_{2} O (l)

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{Na}_{2} O (aq) + 2 H_{2} O (l) + {SO}_{2} (g)

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Solution

The correct option is A ${Na}_{2} {SO}_{4} (aq) + 2 H_{2} O (l)$
$NaOH$ is a base and $H_{2} {SO}_{4}$ is an acid. An acid reacts with a base to give salt and water. This type of reaction is known as neutralisation reaction.

Therefore, $NaOH$ reacts with $H_{2} {SO}_{4}$ to produce ${Na}_{2} {SO}_{4}$ and $H_{2} O$ .
The chemical reaction is given below:

$2 NaOH (aq) + H_{2} {SO}_{4} (aq) \to {Na}_{2} {SO}_{4} (aq) + 2 H_{2} O (l)$

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