Complete the following reaction-a 2NaOH - Cl2 - cold and dilb Cl2 - 3F2 573K- excess

(a) (cold,dilute)2NaOH+Cl_2⟶ NaCl+NaOCl+H_2O (b) Cl_2+3F_2 573K 2ClF_3 ...

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Complete the ...

Question

Complete the following reaction:
a) $2 N a O H + C l_{2} \to$
(cold and dil)
b) $C l_{2} + 3 F_{2} 573 K \to$
(excess)

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2 N a O H c o l d a n d d i l + C l_{2} \to

C l_{2} + 3 F_{2} (e x c e s s) 573 K \to

2 N a O H cold and dilute + C l_{2} \to

2 F e S O_{4} + H_{2} S O_{4} + C l_{2} \to

C l_{2} excess + 3 F_{2} 573 K - -- \to

2 N a O H + C l_{2} \to N a C l +

+ H_{2} O

N a_{2} S O_{3} + 2 H C l \to 2 N a C l + H_{2} O +

C l_{2} + 3 F_{2} 573 K - -- \to

N H_{3} + C l_{2} (e x c e s s) ⟶

$C l_{2} + 2 N a O H \to N a C l + A - - + H_{2} O$ to form. A is

(Cold & dilute)

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