Complete the following reaction by identifying $X$ and $Y$ .
$C H_{3} C H_{2} C \equiv C H N a N H_{2} - ---- \to X C_{2} H_{5} B r - ---- \to Y$

X = C H_{3} C H_{2} C O O N a, Y = C H_{3} C H_{2} C H = C H_{2}

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X = C H_{3} C H_{2} C \equiv C N a, Y = C H_{3} C H_{2} C \equiv C C_{2} H_{5}

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X = C H_{3} C H_{2} C H_{2} C H_{2} N a, Y = C H_{3} C H_{2} C H_{2} C H_{3}

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X = C H_{3} C H_{2} C H \equiv C N a, Y = C H_{3} C H_{2} - C H | C_{2} H_{5} - C H_{3}

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Solution

The correct option is B $X = C H_{3} C H_{2} C \equiv C N a, Y = C H_{3} C H_{2} C \equiv C C_{2} H_{5}$
1-Butyne on reaction with $C_{2} H_{5} B r$ in the presence of $N a N H_{2}$ forms hex-3-yne.
$C H_{3} C H_{2} - C \equiv C H N a N H_{2} - ---- \to {C H_{3} C H_{2} - C \equiv C}^{-} {N a}^{+} (X) C_{2} H_{5} B r - ---- \to C H_{3} C H_{2} - C \equiv C - C H_{2} C H_{3} (Y)$

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