Complete the following reaction:

$H N O_{3} + Z n (O H)_{2} \to$

2 H N O_{3} + Z n (O H)_{2} \to Z n (N O_{3})_{2} + 2 H_{2} O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 H N O_{3} + Z n (O H)_{2} \to 9 Z n (N O_{3})_{2} + H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 H N O_{3} + 8 Z n (O H)_{2} \to Z n (N O_{3})_{2} + H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 H N O_{3} + 8 Z n (O H)_{2} \to Z n (N O_{3})_{2} + 9 H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 H N O_{3} + Z n (O H)_{2} \to Z n (N O_{3})_{2} + 2 H_{2} O$
${H N O}_{3} \to H^{+} + {N O}_{3}^{-}$

As ${H N O}_{3}$ gives $H^{+}$ in water, it is an acid (Arrhenius Theory)

$Z n {(O H)}_{2} \to {Z n}^{+} + {2 O H}^{-}$

As $Z n {(O H)}_{2}$ gives $O H^{-}$ in water, it is a base (Arrhenius Theory)

Hence it is a neutralization reaction.

Neutralization equation:

$A c i d + B a s e$ $\to$ $S a l t + w a t e r$

so, the net equation will be:

${2 H N O}_{3} + Z n {(O H)}_{2} \to Z n {({N O}_{3})}_{2} + 2 H_{2} O$

Hence, the option $(A)$ is correct.

Suggest Corrections

Similar questions

Z n {(O H)}_{2}

[Z n {(O H)}_{2} + H N O_{3} \to Z n (O H) (N O_{3}) + H_{2} O]

2 P_{2} O_{5} + 2 H N O_{3} \to P_{4} O_{10} + H_{2} O + x

2 H N - - O_{3} \to H_{2} O + N_{2} O_{5}

Z n + c o n c . H N O_{3} (h o t) \to Z n (N O_{3})_{2} + X + H_{2} O

Z n + d i l . H N O_{3} (c o l d) \to Z n (N O_{3})_{2} + Y + H_{2} O

X

Y

2 H N O_{3} + C a C O_{3} ⟶

Join BYJU'S Learning Program