Complete the following reaction
(i) $O_{2}^{2 -} + H_{2} O ⟶$

(ii) $O_{2}^{-} + H_{2} O ⟶$

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Solution

(i)

$O_{2}^{2 -}$ represents a peroxide ion
$O_{2}^{-}$ represents a superoide. ion
Peroxide ion react with water to form $H_{2} O_{2} O_{2}^{2 -} + 2 H_{2} O ⟶ 2 O H^{-} + H_{2} O_{2} \begin{matrix} H y d r o g e n p e r o x i d e \end{matrix}$

(ii)

Superoxide ion reacts with water to form $O_{2}$

$2 O_{2}^{-} + 2 H_{2} O ⟶ 2 O H^{-} + H_{2} O_{2} H y d r o g e n p e r o x i d e + \begin{matrix} \end{matrix} O_{2}$

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