Complete the following reaction: Na2CO3(s)+dil.HCl(aq)→
The reaction between Na2CO3 and dilute HCl is a double displacement reaction.
Na2CO3(s)+2HCl(aq)→2NaCl(aq) + H2CO3(aq)
The rapid decomposition of carbonic acid gives out carbon dioxide and water.
H2CO3(aq) → CO2(g) + H2O(l)
So,the final reaction will be:
Na2CO3(s)+2HCl(aq)→ NaCl(aq) + CO2(g) + H2O(l)