Question

Complete the following reaction: $N{a}_{2}C{O}_3\left(s\right)+dil.HCl\left(aq\right)\to$ ___?

• A. $N{a}_{2}C{O}_3+H_{2}O+C{O}_2$
  
• B. $N{a}_{2}S{O}_4+H_{2}O$
  
• C. $N{a}_{2}S{O}_4+C{O}_2$
  
• D. $N{a}_{2}S{O}_4+H_{2}O+C{O}_2$

Answer 1

The correct option is D $N{a}_{2}S{O}_4+H_{2}O+C{O}_2$

The reaction between $N{a}_{2}C{O}_3$ and dilute $HCl$ is a double displacement reaction.
$N{a}_{2}C{O}_3\left(s\right)+2HCl\left(aq\right)\to 2NaCl\left(aq\right)+H_{2}C{O}_3\left(aq\right)$
The rapid decomposition of carbonic acid gives out carbon dioxide and water.
$H_{2}C{O}_3\left(aq\right)\to C{O}_2\left(g\right)+H_{2}O\left(l\right)$
So,the final reaction will be:
$N{a}_{2}C{O}_3\left(s\right)+2HCl\left(aq\right)\to NaCl\left(aq\right)+C{O}_2\left(g\right)+H_{2}O\left(l\right)$