Complete the following reaction $R N H_{2} + H_{2} S O_{4} \to$

[R N H_{3}]^{+} H S O_{4}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[R N H_{3}]_{2}^{+} S O_{4}^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

R N H_{2} . H_{2} S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

No reaction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $[R N H_{3}]_{2}^{+} S O_{4}^{2 -}$
Bases react with acid to form salt.
$∵$ Amines are basic in nature
$∵$ It forms salt on reaction with $H_{2} S O_{4}$
$2 R N H_{2} + H_{2} S O_{4} \to [R N H_{3}]_{2}^{+} S O_{4}^{2 -}$

Suggest Corrections

Similar questions

R N H_{2} + C H {C l}_{3} + 3 K O H ⟶ R N C + 3 K C l + 3 H_{2} O

R N H_{2} + C H C I_{3} + K O H H e a t - -- \to

{R N H}_{2} + S = C = S H_{2} S - --- \to {H g C l}_{2} R - N = C = S A l k y l i s o t h i o c y a n a t e + H_{2} S

H^{+}, H S O_{4}^{-}, S O_{4}^{2 -}

H_{2} S O_{4}

0.20

H_{2} S O_{4} \to H^{+} + H S O_{4}^{-}

H S O_{4}^{-} ⇌ S O_{4}^{2 -}; K_{2} = 10^{- 2}

Complete the following reaction:

$H_{2} {SO}_{4} + 2 NaOH \to$

Join BYJU'S Learning Program