Complete the following reaction:

$S O_{2} + N O + H_{2} O ⟶$ ?

S O_{2} + 2 N O + H_{2} O ⟶ N_{2} O + S O_{4}^{2 -} + 2 H^{+}

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S O_{2} + 4 N O + 2 H_{2} O ⟶ 2 N_{2} O + S O_{4}^{2 -} + 4 H^{+}

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S O_{2} + 2 N O + 4 H_{2} O ⟶ N_{2} O + S O_{4}^{2 -} + 4 H^{+}

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None of these

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Solution

The correct option is B $S O_{2} + 2 N O + H_{2} O ⟶ N_{2} O + S O_{4}^{2 -} + 2 H^{+}$
In acidic medium, sulphur dioxide oxidises to form sulphate ion.
Also, the reaction must be neutral. Hence the overall reaction is:

$S O_{2} + 2 N O + H_{2} O \to N_{2} O + S O_{4}^{2 -} + 2 H^{+}$

So, option A is correct.

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