Complete the following reaction:

$H_{2} {SO}_{4} + 2 NaOH \to$

${Na}_{2} {SO}_{4} + 2 H_{2} O$

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$2 {Na}_{2} {SO}_{4} + H_{2} O$

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$2 {Na}_{2} {SO}_{4} + H_{2} O$

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$2 {Na}_{2} {SO}_{4} + 4 H_{2} O$

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Solution

The correct option is A
${Na}_{2} {SO}_{4} + 2 H_{2} O$

Acids on reaction with a base give salt and water. This reaction between an acid and a base is called a neutralisation reaction. The given reaction is a neutralisation reaction. Here the acid is sulphuric acid $H_{2} {SO}_{4}$ and the base is $NaOH$ . This reaction will give salt ${Na}_{2} {SO}_{4}$ and water $H_{2} O$ . The reaction will occur as follows:

$H_{2} {SO}_{4} (aq) + 2 NaOH (aq) \to {Na}_{2} {SO}_{4} (s) + 2 H_{2} O (l)$

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