Complete the following reactions- i Cr2O2-7 - 3SO2 - 2H- - 2Cr3- - - H2O ii 2Mn O -4 - 5SO2-3 - 6H- - 2MN2- - 3H2O iii Cr2O2-7 - 6Fe2- - 14H- - 2Cr3- 7H2O

The correct option is B 3SO^2 _4, 5SO^2 _4, 6Fe^3+ (i) +5Cr_2O_7^2 ++4 3SO_2+2H^+⟶ 2Cr^3++3+6SO_4^2 +H_2O (ii) 2+7 MnO_4^ ++4 5SO_3^2 +16H^+⟶ 2Mn^ ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Oxides and Oxoanions

Complete the ...

Question

Complete the following reactions.
$(i) C r_{2} O_{7}^{2 -} + 3 S O_{2} + 2 H^{+} \to 2 C r^{3 +} +$ ____ $+ H_{2} O$
$(i i) 2 M n O_{4}^{-} + 5 S O_{3}^{2 -} + 6 H^{+} \to 2 M N^{2 +} +$ ____ $3 H_{2} O$
$(i i i) C r_{2} O_{7}^{2 -} + 6 F e^{2 +} + 14 H^{+} \to 2 C r^{3 +}$ ____ $7 H_{2} O$

3 S O_{4}^{2 -}, S O_{2}^{2 -}, F e^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 S O_{4}^{2 -}, 5 S O_{4}^{2 -}, 6 F e^{3 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 S O_{4}^{2 -}, S O_{2}, K^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S, S O_{2}, F e^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $3 S O_{4}^{2 -}, 5 S O_{4}^{2 -}, 6 F e^{3 +}$
(i) $+ 5 C r_{2} O_{7}^{2 -} + + 4 3 S O_{2} + 2 H^{+} ⟶ 2 C r^{3 +} + 3 + 6 S O_{4}^{2 -} + H_{2} O$
(ii) $2 + 7 M n O_{4}^{-} + + 4 5 S O_{3}^{2 -} + 16 H^{+} ⟶ 2 M n^{2} + + 6 5 S O_{4}^{2 -} + 3 H_{2} O$
(iii) $+ 5 C r_{2} O_{7}^{2 -} + 6 F e^{2 +} + 14 H^{+} ⟶ 2 C r^{3 +} + 6 F e^{3 +} + 7 H_{2} O$

Suggest Corrections

Similar questions

4 F e S + 7 O_{2} ⟶ 2 F e_{2} O_{3} + 4 S O_{2}

C r_{2} O_{7}^{2 -} + 2 H^{+} + 3 S O_{2} ⟶ 2 C r^{3 +} + 3 S O_{4}^{2 -} + H_{2} O

1 g

sample of

F e S

was roasted with oxygen gas

S O_{2}

thus formed required

10 m L

0.05 M K_{2} C r_{2} O_{7}

solution in acidic medium. Calculate percentage of

F e S

in the sample.

(F e = 56, S = 32)

Q. Given a reaction:

{C r}_{2} O_{7}^{2 -} + {F e}^{2 +} + H^{\oplus} ⟶ {C r}^{3 +} + {F e}^{3 +} + H_{2} O

The balanced equation is

6 {F e}^{2 +} + 14 H^{\oplus} + {C r}_{2} O_{7}^{2 -} ⟶ 6 {F e}^{3 +} + 2 {C r}^{3 +} + 7 H_{2} O

.
If true enter 1, else enter 0.

S + 2 H_{2} S O_{4} (c o n c .) \to 3 S O_{2} + 2 H_{2} O

C r_{2} O_{7}^{_{2}} + H_{2} O + 3 S O_{2} \to 2 C r^{+ 3} + 2 O H^{-} + 3 S O_{4}^{- 2}

write down to oxidation and reduction reaction

Q. Identify the reducing agent in the redox reaction

5 S O_{3}^{2 -} + 2 M n O_{4}^{-} + 6 H^{+} \to 5 S O_{4}^{2 -} + 2 M n^{2 +} + 3 H_{2} O

Join BYJU'S Learning Program

Complete the following reactions.(i)Cr2O2−7+3SO2+2H+→2Cr3++____ +H2O(ii)2MnO−4+5SO2−3+6H+→2MN2++____ 3H2O(iii)Cr2O2−7+6Fe2++14H+→2Cr3+____7H2O

The correct option is B 3SO2−4,5SO2−4,6Fe3+(i)+5Cr2O2−7++43SO2+2H+⟶2Cr3++3+6SO2−4+H2O(ii)2+7MnO−4++45SO2−3+16H+⟶2Mn2++65SO2−4+3H2O(iii)+5Cr2O2−7+6Fe2++14H+⟶2Cr3++6Fe3++7H2O

Complete the following reactions.
$(i) C r_{2} O_{7}^{2 -} + 3 S O_{2} + 2 H^{+} \to 2 C r^{3 +} +$ ____ $+ H_{2} O$
$(i i) 2 M n O_{4}^{-} + 5 S O_{3}^{2 -} + 6 H^{+} \to 2 M N^{2 +} +$ ____ $3 H_{2} O$
$(i i i) C r_{2} O_{7}^{2 -} + 6 F e^{2 +} + 14 H^{+} \to 2 C r^{3 +}$ ____ $7 H_{2} O$