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Question
Complete the following reactions:
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Solution
(i)Cynohydrin will be formed in this reaction by following mechanism.
(ii) Dialkyl cadmium when treated with acid chloride will replace the alkyl group with chloride group to form a ketone. Since dialkyl cadmium is less reactive than Grignard's reagent, it will not further react with ketone.
(C6H5CH2)2Cd+2CH3COCl→2C6H5CH2COCH+CdCl2
(iii) The carboxylic acid present in reactant has α hydrogen, which when treated with red P/Br2 will undergo Hell-Volhard-Zelinsky reaction to replace the α hydrogen with a Halogen.
(ii) Dialkyl cadmium when treated with acid chloride will replace the alkyl group with chloride group to form a ketone. Since dialkyl cadmium is less reactive than Grignard's reagent, it will not further react with ketone.
(C6H5CH2)2Cd+2CH3COCl→2C6H5CH2COCH+CdCl2
(iii) The carboxylic acid present in reactant has α hydrogen, which when treated with red P/Br2 will undergo Hell-Volhard-Zelinsky reaction to replace the α hydrogen with a Halogen.
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