Question

Complete the given table when $FeS{O}_4$ reacts with $NaOH$ and $N{H}_{4}OH$.

$\begin{array}{ccc}\text{For}Pb(N{O}_3{)}_2& \text{NaOH}& N{H}_{4}OH\\ \text{Colour}& \text{Dirty green precipitate}& X\\ \text{Solubility}& Y& \text{Precipitate formed will be}\\ & & \text{insoluble in excess}NaOH\end{array}$

• A. X : Chalky white precipitate
  Y : Precipitate formed will be soluble in excess $NaOH$
• B. X : Dirty green precipitate
  Y : Precipitate formed will be soluble in excess $NaOH$
• C. X : Dirty green precipitate
  Y : Precipitate formed will be insoluble in excess $NaOH$
• D. X : Gelatinous white precipitate
  Y : Precipitate formed will be soluble in excess $NaOH$

Answer 1

The correct option is C X : Dirty green precipitate

Y : Precipitate formed will be insoluble in excess $NaOH$
$\begin{array}{ccc}\text{For}FeS{O}_4& \text{NaOH}& N{H}_{4}OH\\ \text{Colour}& \text{Dirty green precipitate}& \text{Dirty green precipitate}\\ \text{Solubility}& \text{Precipitate formed will be}& \text{Precipitate formed will be}\\ & \text{insoluble in excess NaOH}& \text{insoluble in excess}NaOH\end{array}$
$FeS{O}_4\left(aq\right)+2NaOH\left(aq\right)\to N{a}_{2}S{O}_4\left(aq\right)+Fe\left(OH{)}_2\right(ppt.)$
$FeS{O}_4\left(aq\right)+2N{H}_{4}OH\left(aq\right)\to \left(N{H}_4{)}_{2}S{O}_4\right(aq)+Fe(OH{)}_2(ppt.)$