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Question

Complete the given table when Pb(NO3)2 reacts with NaOH and NH4OH.

For Pb(NO3)2NaOHNH4OHColourChalky white precipitateXSolubilityPrecipitate formed will be solubleYin excess NaOH


A
X : Dirty green precipitate
Y : Precipitate formed will be soluble in excess NH4OH
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B
X : Gelatinous white precipitate
Y : Precipitate formed will be insoluble in excess NH4OH
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C
X : Chalky white precipitate
Y : Precipitate formed will be insoluble in excess NH4OH
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D
X : Chalky white precipitate
Y : Precipitate formed will be soluble in excess NH4OH
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Solution

The correct option is C X : Chalky white precipitate
Y : Precipitate formed will be insoluble in excess NH4OH
ForPb(NO3)2NaOHNH4OHColourChalky white precipitateChalky white precipitateSolubilityPrecipitate formed is solublePrecipitate formed will be insoluble in excess NH4OH
Pb(NO3)2(aq) + 2NaOH(aq) 2NaNO3(aq) + Pb(OH)2(ppt.)
Pb(NO3)2(aq) + 2NH4OH 2NH4NO3(aq) + Pb(OH)2(ppt.)
The formed precipitate, i.e. Pb(OH)2 will be soluble in excess NaOH while insoluble in excess NH4OH.

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