Complete the given table when Pb(NO3)2 reacts with NaOH and NH4OH.
ForPb(NO3)2NaOHNH4OHColourChalky white precipitateXSolubilityPrecipitate formed will be solubleYin excess NaOH
A
X : Dirty green precipitate
Y : Precipitate formed will be soluble in excess NH4OH
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B
X : Gelatinous white precipitate
Y : Precipitate formed will be insoluble in excess NH4OH
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C
X : Chalky white precipitate
Y : Precipitate formed will be insoluble in excess NH4OH
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D
X : Chalky white precipitate
Y : Precipitate formed will be soluble in excess NH4OH
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Solution
The correct option is C X : Chalky white precipitate
Y : Precipitate formed will be insoluble in excess NH4OH ForPb(NO3)2NaOHNH4OHColourChalky white precipitateChalky white precipitateSolubilityPrecipitate formed is solublePrecipitate formed will be insoluble in excessNH4OH Pb(NO3)2(aq)+2NaOH(aq)→2NaNO3(aq)+Pb(OH)2(ppt.) Pb(NO3)2(aq)+2NH4OH→2NH4NO3(aq)+Pb(OH)2(ppt.) The formed precipitate, i.e. Pb(OH)2 will be soluble in excess NaOH while insoluble in excess NH4OH.