Complete the given thermal cracking reaction:
$C H_{3} C H_{2} C H_{3} (g) \to$

C H \equiv C H (g) + C H_{4} (g)

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C H_{2} = C H_{2} (g) + C H_{4} (g)

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C H_{2} = C H_{2} (g)

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C H_{3} C H_{3} (g) + C H_{4} (g)

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Solution

The correct option is B $C H_{2} = C H_{2} (g) + C H_{4} (g)$
The reaction in which hydrocarbons with high molecular masses, on heating in the absence of air, form hydrocarbons with lower molecular masses is known as a thermal cracking reaction.

However, the total number of carbon and hydrogen atoms present in the hydrocarbon with higher molecular mass will be equal to the number of carbon and hydrogen atoms of product present in total.

In the given reaction propane will undergo thermal cracking to form methane and ethene. The chemical reaction for the same is given below:
$C H_{3} C H_{2} C H_{3} (g) \to C H_{2} = C H_{2} (g) + C H_{4} (g)$

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Similar questions

Complete the given thermal cracking reaction:

$C H_{3} C H_{2} C H_{3} (g) \to$

$C_{6} H_{14} (g) \to C_{2} H_{6} (g) + C_{4} H_{8} (g)$

The given reaction is an example of thermal cracking reaction.

$C H_{3} C H_{2} C H_{2} C H_{3} (g) \to C H_{3} C H_{3} (g) + P$

The given reaction is a thermal cracking reaction. Identify P.

Heptane Thermal cracking - --------- \to A + B

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