Question

Complete the last column of the table:

$\begin{array}{cccc}\text{S.No.}& \text{Equation}& \text{Value}& \text{Say, whether the equation is satisfied (yes/no)}\\ \left(i\right)& x+3=0& x=3& \\ \left(ii\right)& x+3=0& x=0& \\ \left(iii\right)& x+3=0& x=-3& \\ \left(iv\right)& x-7=1& x=7& \\ \left(v\right)& x-7=1& x=8& \\ \left(vi\right)& 5x=25& x=0& \\ \left(vii\right)& 5x=25& x=5& \\ \left(viii\right)& 5x=25& x=-5& \end{array}$

Answer 1

In each equation, substitute the given value of $x$ in LHS and then compare with RHS.

If LHS $=$ RHS then write YES.

If LHS $\ne$ RHS then write NO.

$\begin{array}{cccc}\text{S.No.}& \text{Equation}& \text{Value}& \text{Say, whether the equation is satisfied (yes/no)}\\ \left(i\right)& x+3=0& x=3& 3+3=6\ne 0,\text{NO}\\ \left(ii\right)& x+3=0& x=0& 0+3=3\ne 0,\text{NO}\\ \left(iii\right)& x+3=0& x=-3& -3+3=0,\text{YES}\\ \left(iv\right)& x-7=1& x=7& 7-7=0\ne 1,\text{NO}\\ \left(v\right)& x-7=1& x=8& 8-7=1,\text{YES}\\ \left(vi\right)& 5x=25& x=0& 5\times 0=0,\ne 25,\text{NO}\\ \left(vii\right)& 5x=25& x=5& 5\times 5=25,\text{YES}\\ \left(viii\right)& 5x=25& x=-5& 5\times -5=-25\ne 25,\text{NO}\end{array}$