Question

Complete the proof of the theorem 'Angles in the same arc are congruent' with the help of given figure.
Arc intercepted by $\angle ABC=$
Arc intercepted by $\angle ADC=$
$=\frac{1}{2}m\left(arcAXC\right)......\left(I\right)$
$=\frac{1}{2}m\left(arcAXC\right)......\left(II\right)$
From $\left(I\right)$ and $\left(II\right)$
$\therefore \angle ABC\cong \angle ADC$

Answer 1

Angle abc is equal to angle $ADC$ are intersected by angle $abc$ is a $C$.

$\begin{array}{c}m\left(arcAXC\right)\\ m\left(arcAXC\right)\\ angleABC\\ angleABC\end{array}$